方法一:采用正则表达式获取地址栏参数 (代码简洁,重点正则)
function getQueryString(name) {
let reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i");
let r = window.location.search.substr(1).match(reg);
if (r != null) {
return unescape(r[2]);
};
return null;
}
调用方法:
let 参数1 = GetQueryString("参数名1"));
方法二:split拆分法 (代码较复杂,较易理解)
function GetRequest() {
const url = location.search; //获取url中"?"符后的字串
let theRequest = new Object();
if (url.indexOf("?") != -1) {
let str = url.substr(1);
strs = str.split("&");
for(let i = 0; i < strs.length; i ++) {
theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);
}
}
return theRequest;
}
调用方法:
let Request = new Object();
Request = GetRequest();
var 参数1,参数2 ...;
参数1 = Request['参数1'];
参数2 = Request['参数2'];
参数... = Request['参数...'];
方法三:split拆分法(易于理解,代码中规)
function getQueryVariable(variable){
let query = window.location.search.substring(1);
let vars = query.split("&");
for (let i=0;i<vars.length;i++) {
let pair = vars[i].split("=");
if(pair[0] == variable){return pair[1];}
}
return(false);
}
调用方法:
let 参数1 = getQueryVariable("参数名1");
http://www.jianshu.com/search?q=123&page=1&type=note
http:
www.jianshu.com
空字符(如果采用默认的80端口(update:即使添加了:80),那么返回值并不是默认的80而是空字符)
/search
?q=123&page=1&type=note
空字符(因为url中没有)