7种JOIN的实现:
SELECT employee_id,department_name
FROM employees e JOIN departments d
ON e.department_id
= d.department_id
;
SELECT employee_id,department_name
FROM employees e LEFT JOIN departments d
ON e.department_id
= d.department_id
;
SELECT employee_id,department_name
FROM employees e RIGHT JOIN departments d
ON e.department_id
= d.department_id
;
SELECT employee_id,department_name
FROM employees e LEFT JOIN departments d
ON e.department_id
= d.department_id
WHERE d.department_id
IS NULL;
SELECT employee_id,department_name
FROM employees e RIGHT JOIN departments d
ON e.department_id
= d.department_id
WHERE e.department_id
IS NULL;
SELECT employee_id,department_name
FROM employees e LEFT JOIN departments d
ON e.department_id
= d.department_id
UNION ALL
SELECT employee_id,department_name
FROM employees e RIGHT JOIN departments d
ON e.department_id
= d.department_id
WHERE e.department_id
IS NULL;
SELECT employee_id,department_name
FROM employees e LEFT JOIN departments d
ON e.department_id
= d.department_id
WHERE d.department_id
IS NULL
UNION ALL
SELECT employee_id,department_name
FROM employees e RIGHT JOIN departments d
ON e.department_id
= d.department_id
;
SELECT employee_id,department_name
FROM employees e LEFT JOIN departments d
ON e.department_id
= d.department_id
WHERE d.department_id
IS NULL
UNION ALL
SELECT employee_id,department_name
FROM employees e RIGHT JOIN departments d
ON e.department_id
= d.department_id
WHERE e.department_id
IS NULL;